Visit this page directly at hunkim.com/10i
- Sine, cosine, and tangent ratios
- Right-triangle problems: determining missing sides and/or angles using trigonometric ratios and the Pythagorean theorem
- Contexts involving direct and indirect measurement
- Explain the acronym SOH CAH TOA
Solution\sin \theta=\frac{\text{opposite}}{\text{hypotenuse}}, \cos \theta=\frac{\text{adjacent}}{\text{hypotenuse}}, \tan \theta=\frac{\text{opposite}}{\text{adjacent}} - Use the correct mathematical notation to incidicate that \angle ABC=90^\circ
Solution
- By convention angles in triangles are in uppercase. By convention, how should you label the sides of the triangle?
SolutionLowercase letters are placed opposite the corresponding angle - What kind of triangles does SOH CAH TOA work with?
SolutionRight triangles - See triangle below:

- Find \sin \theta
Solution\frac{3}{5} - Find \cos \theta
Solution\frac{4}{5} - Find \tan \theta
Solution\frac{3}{4} - Find \sin \alpha
Solution\frac{4}{5} - Find \cos \alpha
Solution\frac{3}{5} - Express \cos \alpha as a decimal number
Solution0.6 - Find \tan \alpha
Solution\frac{4}{3} - Find \theta in degrees
Solution\approx 36.9^\circ - Find \alpha in degrees
Solution\approx 53.1^\circ
- Find \sin \theta
- See triangle below:

- Find x
Solution\sqrt{3} - Find \theta
Solution30^\circ - Find \sin 60^\circ
Solution\frac{\sqrt{3}}{2}
- Find x
- See the right triangle below:

- Find \sin \theta
Solution\frac{5}{13} - Find \cos \theta
Solution\frac{12}{13} - Find \tan \theta
Solution\frac{5}{12} - Find \sin \alpha
Solution\frac{12}{13} - Find \cos \alpha
Solution\frac{5}{13} - Find \tan \alpha
Solution\frac{12}{5} - Find \alpha using two different trigonometric ratios
Solution\alpha=\cos^{-1}\left(\frac{5}{13}\right)=\tan^{-1}\left(\frac{12}{5}\right)\approx 67.4^\circ
- Find \sin \theta
- How tall is the tree below?

Solution10\tan 30^\circ=\frac{10\sqrt{3}}{3}\approx 7.77 - Your friend is 6’ tall and stands 12 steps sway from the school. Each step measures 2’. Using a clinometer, you find that the roof of the school is at an angle of elevation of 45^\circ. The diagram below is not to scale:

- Find the height of your school without using SOH CAH TOA.
Solution30' - Find the height of your school using SOH CAH TOA.
Solution30'
- Find the height of your school without using SOH CAH TOA.
- How far apart is person A from person B?

Solution33.2 - Find length AB in the triangle below:

Solution11.9