Here you will find a collection of concise function transformation practice problems. Visit this page directly at hunkim.com/transformations
- f(x)=x2
Describe the transformation:- y=f(x)+2
SolutionShift 2 units up
- y=f(x−3)
SolutionShift 3 units to the right
- y=−2f(x)+1
SolutionMultiply y’s by
−2, shift 1 unit up
- y=f(2x)
SolutionMultiply x’s by
21 - y=3f(3(x−1))+2
SolutionMultiply y’s by 3, multiply x’s by
31, shift 1 right and 2 up
- f(x)=x2
What is the actual equation of y=2f(3x)−1?
Click here if you need to review function substitution.
Solutiony=18x2−1 - f(x)=x2. g(x)=f(2x−6)
Describe the horizontal translation of g(x) as compared to f(x)
SolutionShift 3 units right
- f(x)=(x−2)(x−6). g(x)=2f(x+1)
Find the equation of the line of symmetry of g(x)
Solution - f(x)=x2. g(x)=f(−x)
What happens to the point (3,9) on f(x) in this transformation?
SolutionMoves to
(−3,9) - f(x)=x2. g(x)=f(x+3)−1
- Describe this transformation using vector notation
(pq)
Solutionp=−3 and
q=−1 - Describe this transformation using mapping notation (x,y)→(?,?)
Solution(x,y)→(x−3,y−1)
- Describe the transformation of:
- y=f(32x−54)
SolutionMultiply x’s by
23, shift
56 to the right
- h(t)=f(0.2t−2π)+e
SolutionMultiply x’s by
5, shift
25π right and
e units up
- f(x)=x2. g(x)=9f(x)
- h(x) is a horizontal transformation of f(x).
Also h(x)=g(x)
Then h(x)=f(kx). Find k
Solution - Challenge: Given f(5x)=kf(3x), find k
Solution
- f(x)=2x+3. g(x)=32f(1−2x)
What happens to the point (1,5) on f(x) after the transformation?
SolutionMoves to
(0,310) - We have mainly focused on transforming quadratics. However all functions can be transformed. Try to memorize the following key base functions:
- f(x)=x2
- f(x)=2x
- f(x)=(1/2)x
- f(x)=logx
- f(x)=x1
- f(x)=sinx
- f(x)=cosx
- f(x)=tanx
- See f(x) below:

Sketch y=−2f(x−1)−3 on top of the graph above
Solution
- Enrichment: Produce the following function using piecewise notation on Desmos and transform the graph using parameter sliders: y=af(b(x±c))±d

Solution
- Enrichment: Memorize some additional base functions that can be transformed:
- y=⌊x⌋
Solution
- y=x∣x∣
Solution
- g(x)=x+12x−3 and f(x)=x1
- Describe g(x) as a transformation of f(x)
SolutionMultiply y’s by
−5, shift 1 left and 2 up
- Describe the transformation to move the center of g(x) to the origin
SolutionMove 1 right, 2 down
- Enrichment: Reciprocal transformations
- f(x)=2x+3. Sketch g(x)=f(x)1
- f(x)=(x−2)2−1. Sketch g(x)=f(x)1
- f(x)=x2+4. Sketch g(x)=f(x)1
- Enrichment: Given f(x) below, roughly sketch f(x) and state the invariant points
- f(x)=x2+4
- f(x)=x2−4
- f(x)=4−x2
- f(x)=−x2−4
- f(x)=2−x
- Enrichment: f(x)=x(x−2)
- Sketch y=∣f(x)∣
- Sketch y=f(∣x∣)
- Sketch y=f(∣x∣−2)
- Sketch y=−2∣f(x−2)∣
- Sketch y=f(∣2x−4∣−2)
- Challenge: g(x)=2x−32−3x
Describe g(x) as a transformation of f(x)=x1
SolutionMany correct solutions (verify on Desmos). For example: Multiply y’s by
−5, multiply x’s by
41, shift
23 right and
23 down
