Here you will find a concise collection of arithmetic and geometric sequences and series practice problems. Visit this page directly by visiting hunkim.com/sequences or hunkim.com/seq
Overview:
Arithmetic Sequences and Series
- Arithmetic sequence: t_n=t_1+(n-1)d
- Arithmetic series:
- S_n=\frac{n}{2}(t_1+t_n)
- S_n=\frac{n}{2}\left(2t_1+(n-1)d\right)
- 2, 5, 8, 11, ...
- Express this pattern as a line equation
Solutiony=3x-1 - Express this pattern using the arithmetic sequence formula t_n = t_1 + (n-1)d
Solutiont_n=2+(n-1)(3) - Justify why this formula makes sense
SolutionWe start at the value of the first term. We then add multiples of the common difference d to achieve the unknown term t_n - Find the 100th term of this sequence
Solution299
- Express this pattern as a line equation
- 20, 17, 14, ... -37. How many terms are in this sequence?
Solution20 - \frac{2}{3} and 1 \frac{1}{2} are the first two terms of an arithmetic sequence. Find the 4th term
Solution\frac{19}{6} - 3.\bar{3} and 4.\bar{6} are the 4th and 5th terms of an arithmetic sequence. Find the first term
Solution-\frac{2}{3} - The third term of an arithmetic sequence is 11 and the 15th term has a value of 47. Find the value of the 30th term.
Solution62 - Enrichment: Understanding the arithmetic series formula
- Explain why S_n=\frac{n}{2}\left(2t_1+(n-1)d\right)
SolutionSee proof here - Why is this formula equivalent to S_n=\frac{n}{2}(t_1+t_n)
SolutionSubstitute t_n=t_1+(n-1)d into the other formula
- Explain why S_n=\frac{n}{2}\left(2t_1+(n-1)d\right)
- 7, 4, 1, -2, ..., -50. Find the sum of these terms
Solution-430 - Express the sum of 1+2+3+4+5+...+n as a formula in terms of n
SolutionS_n=\frac{n}{2}\left(1+n\right) - Find the sum of all the multiples of 3 between 50 and 5000
Solution4165425 - An arithmetic sequence has first term 3 and common difference 6. If the sum of all terms is 4800, how many terms are in the sequence?
Solution40 - -10, -6, -2, 2, ... Find the least number of terms so that the sum of the series is greater than 960
Solution26 - The sum of the first n terms of an arithmetic sequence is
S_n=5n^2-3n. Find the nth term t_n
Solution10n-8 - What is the sum of all three-digit numbers which are multiples of 6 but not 9?
Solution54900 - S_{10}=285 and S_{14}=539. Find S_5, the sum of the first 5 terms in an arithmetic series
Solution80 - Enrichment:
- Given t_n=3n-2 simplify an expression for t_{n+1}-t_n
Solution3 - t_1=1 and t_2=1. Given t_n=t_{n-1}+t_{n-2}, find t_4
Solution3
- Given t_n=3n-2 simplify an expression for t_{n+1}-t_n
- Sigma notation:
- \sum_2^5{x}
Solution14 - \sum_0^2 \left(x^2-3x\right)
Solution-6 - \sum_{-1}^2{\frac{x}{3}}
Solution\frac{2}{3} - \sum_1^4{\frac{2\pi r}{e}}
Solution\frac{20\pi}{e} - Evaluate \sum_2^4\left(3^r-1\right)
Solution116 - T_n=\sum_0^n\left(r^2-2r\right). Find T_2
Solution-1
- \sum_2^5{x}
- How many terms does \sum_{5}^{100}r have?
Solution96 - Find the sum of the numbers between 500 and 2000 that are multiples of 3
Solution624750 - Write in sigma notation:
- 10+7+4+1
Solution\sum_1^4(-3n+13) - \frac{2}{3}+\frac{3}{4}+\frac{4}{5}+\frac{5}{6}
Solution\sum_2^5\frac{r}{r+1} or \sum_3^6\frac{r-1}{r} - Challenge: \frac{2x}{\pi}+\frac{5x}{2\pi}+\frac{8x}{3\pi}
Solution\sum_1^3\frac{(3n-1)x}{n\pi}
- 10+7+4+1
- S_1=1, S_2=1+3, S_3=1+3+5, S_4=1+3+5+7... Evaluate S_n in terms of n
SolutionS_n=n^2 - Challenge:
- Challenge: 3\sqrt{3} and 2\sqrt{27} are respectively the second and the thrid terms of an arithmetic sequences. Find the value of the 5th term
Solution12\sqrt{3} - The first four terms of an arithmetic sequence are:
4, 3b-a, 4a+b-1, 5b-a. Find a and b
Solutiona=2, b=3 - 2a, a+2b, 5b-2a are the first three terms of an arithmetic sequence
- Find an expression for the 5th term
Solution-2a+8b - Express a in terms of b
Solutiona=\frac{b}{2} - Given t_4=11, find a
Solution1
- Find an expression for the 5th term
- A circular is cut into 8 sectors whose angles are in an arithmetic sequence. The angle of the largest sector is triple the angle of the smallest sector. Find the angle of the largest sector.
Solution67.5^\circ - The ratio of the 4th term to the 10th term of an arithmetic sequence is 11:23. If each term of this sequence is positive and the product of the first term and the third term is 45, find the sum of the first 100 terms of the sequence.
Solution104000 - An arithmetic sequence has the first term \ln a and a common difference \ln 2. The 14th term in the sequence is 4\ln 16. Find the value of a
Solution8
- Challenge: 3\sqrt{3} and 2\sqrt{27} are respectively the second and the thrid terms of an arithmetic sequences. Find the value of the 5th term
Geometric Sequences and Series
- Geometric sequence: t_n=t_1r^{n-1}
- Geometric series: S_n=\frac{t_1(1-r^n)}{1-r}
- Infinite geometric series: S_\infty=\frac{a}{1-r}
- 3, 6, 12, 24, ... Find the 10th term using the geometric series formula: t_n=t_1 r^{n-1}
Solution1536 - 1024, 512, 256, ... \frac{1}{4}. How many terms in this sequence?
Solution13 - In a geometric sequence, the 2nd term is 28 and the 5th term is 1792. Find t_1
Solution7 - 0.2+0.002+0.00002+...
- Find t_1
Solution0.2 - Find r
Solution0.01
- Find t_1
- 3, 12, 48, 5y+7, ... Find y
Solution37 - The first three terms of a geometric sequence are:
t_1=0.32, t_2=1.28, and t_3=5.12.- Find the value of r
Solution4 - Find the value of S_5
Solution109.12 - Find the least value of n such that S_n>30,000
Solution10
- Find the value of r
- You jog to school. During the first minute you jog 60 metres. In each subsequent minute you walk 95% of the distance jogged during the previous minute. The distance between your house and school is 1000 metres. You leave your house at 8 am. What time will it be when you arrive at school?
Solution8:35 am - A ball is dropped vertically from a height of 12 m. After each bound it rises to 80% of its previous height
- What height does the ball reach after the 4th bounce?
SolutionAbout 4.92 m - After how many bounces will the ball reach an approximate height of 10 cm?
Solution21 or 22 bounces - What is the total vertical distance travelled by the ball as soon as the ball bounces 10 times?
SolutionAbout 95.1 m - What is the total distance travelled by the ball if it bounces indefinitely?
SolutionAbout 108 m
- What height does the ball reach after the 4th bounce?
- You inherited $5000 at the beginning of the year 2020. Assuming a growth rate of 10%, how much money will you investment grow to be by the end of the year 2070?
SolutionAbout $586,954.26 - The sum of an infinite geometric sequence is 25. The common ratio is \frac{4}{5}. Find the first term
Solution\frac{125}{4} - Three consecutive terms of a geometric sequence are:
x-5, x-2, x+4. Find the value of the first of these three terms
Solution3 - \sum_{2}^{10}3^r
- Find r
Solution3 - Evaluate
Solution265716
- Find r
- S_1=1+k, S_2=4k+2, S_3=8k+5
- Express t_1 in terms of k
Solutiont_1=1+k - Find t_3
Solution4k+3
- Express t_1 in terms of k
- t_n=n3^n
- Find t_1
Solution3 - Simplify \frac{t_{n+1}}{t_n}
Solution\frac{3n+3}{n}
- Find t_1
- 9, 3, 1, .... Find S_\infty
Solution\frac{27}{2} - 4, 6, 9, \frac{27}{2}, .... Find S_\infty
SolutionNo solution, this series diverges - See figures below:
Fig 1:
Fig 2:
Fig 3:- If the side length of figure 1 is 16 metres what is the shaded region of figure 10?
Solution\approx2.44\times10^{-4} - If the side length of figure 1 is k metres, what is the area of the non-shaded region as n\to\infty?
Solution\frac{2k^2}{3}
- If the side length of figure 1 is 16 metres what is the shaded region of figure 10?
- Challenge:
- Solve \sum_{k=1}^{\infty} \left(3^{3-k} \log x\right)=\frac{200}{9}
Solution10^{\frac{400}{81}} - A book starts at page 1 and is numbered on every page.
- How many page digits in total are there on the first dozen pages?
Solution15 - If the total number of digits used is 252, how many pages are in the book?
Solution120
- How many page digits in total are there on the first dozen pages?
- Evaluate \sum_{n=0}^{n=\infty} \frac{2^n+4^n}{6^n}
Solution\frac{9}{2} - The first three terms of a geometric sequence are \log x^9, \log x^3, \log x, for x>0. Find the common ratio
Solution\frac{1}{3}
- Solve \sum_{k=1}^{\infty} \left(3^{3-k} \log x\right)=\frac{200}{9}